If alpha and beta are the zeros of the quadratic polynomial f(x) = x^2-4x+3 . find the value of alpha^3*beta^4+alpha^4*beta^3
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3
Answer:
108
Step-by-step explanation:
alpha + beta = 4 & alpha * beta = 3
let alpha be a & beta be b
a^3*b^4 + a^4*b^3 = a^3*b^3 (a+b)
= (ab)^3 * (a+b)
= 3³ * 4 = 27*4 = 108
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