if alpha and beta are the zeros of the quadratic polynomial x square - p[x-1]-C ,show that [alpha -1] [beta +1]= 1-C
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Answer:
alpha
Step-by-step explanation:
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polynomial
= x²-p(x-1) - C
= x²- px + (p - C)
therefore
(alfa-1) ( beta+1)
= alfa× beta + alfa-beta -1
= (p-C)/1 + √ ( alfa - beta)²-1
= ( p-C) + √ [( alfa+ beta)²- 4alfa× beta] -1
= ( p- C) + √[( p/1)²-4(p-C)]-1
= ( p- C) +√ ( p²-4p+ 4C)- 1
solving these gives
1-C
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