if alpha and beta are the zeros of the quadratic polynomial 3x square + 5 x + X evaluate one by Alpha plus one by beta
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Step-by-step explanation:
As I’m lazy, I won’t use Greek letters for the roots; instead, I will use p and q. As these are the roots of your quadratic, then:
2x2+5x−10=2(x−p)(x−q)=2x2−2(p+q)x+2pq
Thus 2pq=−10→pq=−5
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Answer:
-5/7
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