If alpha and beta are the zeros of the quadratic polynomial f x is equals to a x square + bx + c then evaluate one upon Alpha minus one upon beta
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f(x) = ax²+bx+c
We know that, alpha + beta = (-b/a) ; alpha×beta = c/a
We also know that, (1/alpha - 1/beta)² = (b²-4ac)/c²
Therefore, 1/alpha - 1/beta = ±√(b²-4ac)/c
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