if alpha and beta are the zeros of the quadratic polynomial f(x) = x^2 - 1 , find a quadratic polynomial whose zeroes are 2α/β and 2β/α
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Answered by
84
Step-by-step explanation:
f(x)=x²-1
Roots are Alpha ,beta
Alpha +Beta=-b/a=0
Alpha×beta=c/a=-1
Now we have to Find Polynomial whose Root are 2alpha/beta,2beta/alpha
Now we Structure of Quadratic Equation
ax²+(sum of Roots)x+product of Roots
So sum of Roots
2alpha/beta+2beta/alpha
2alpha²+2beta²/alpha×beta
(For Convience i m taking alpha=x,beta=y)
2x²+2y²/xy
2(x²+y²)/xy
We know
(x+y)²-2xy=x²+y²
0²-2×-1=x²+y²
x²+y²=2
xy=-1
Sum of Roots 4/-1=-4
Product of Roots
4xy/xy
=4
Sum=-4
product=4
Quadratic Equation
x²+4x+4
p(x)=x²+4x+4
Answered by
3
p(x)=x raiseto power2 +4x+4
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