if alpha and beta are the zeros of the quadratic polynomial FX equal to X square + X - 2, find the value of one upon Alpha minus one upon beta . kisi mai dam hai to pure step se solve karke dikha too mann jaunga
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Step-by-step explanation:
f(x) = x² + x - 2
a = 1 , b = 1 , c = -2
Let α and β be the zeroes of the polynomial.
sum of zeroes = α + β = -b/a = - 1/1 = 1
Product of zeroes = αβ = c/a = -2/1 = -2.
(α - β)² = (α + β)² - 4αβ
= (-1)² - 4 (-2)
= 1 + 8
= 9
α - β = ±3
When α - β = + 3,
1/α - 1/β = β - α / αβ = - (α - β) / αβ = - (+3)/ - 2 = 3/2
When α - β = - 3,
1/α - 1/β = β - α / αβ = - (α - β) / αβ = -(-3) / - 2 = -3/2
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