Math, asked by srushtisp2005, 7 months ago

if alpha and beta are the zeros of the quadratic polynomial 3 X ^2 + 5 x + 7 evaluate 1. 1 by alpha + 1 by beta 2. 1 alpha ^2 + 1 betta ^2​

Answers

Answered by BrainlyGorgeous
14

Answer :

  1. 1/α + 1/β = -5/7
  2. 1/α² + 1/β² = -17/49

Solution :

3x² + 5x + 7 = 0

α + β = -b/a = -5/3

αβ = c/a = 7/3

 \frac{1}{ \alpha }  +  \frac{1}{ \beta }

 \frac{ \alpha  +  \beta }{ \alpha  \beta }

 \frac{ \frac{ - 5}{3} }{ \frac{7}{3} }

 \frac{ - 5}{7}

 \frac{1}{ { \alpha }^{2} }  +  \frac{1}{ { \beta }^{2} }

 \frac{  { \alpha }^{2} +  { \beta }^{2}  }{ ( \alpha  \beta)^{2} }

 \frac{( \alpha  +  \beta )^{2} - 2 \alpha  \beta  }{( \alpha  \beta)^{2} }

 \frac{( { \frac{ - 5}{3}) }^{2} - 2 (\frac{7}{3})  }{( { \frac{7}{3} )}^{2} }

 \frac{(25 - 42)}{49}

 \frac{ - 17}{49}

Similar questions