if alpha and beta are the zeros of the quadratic polynomial p(x)=4x²-5x-1 find the value of alpha²beta+alphabeta²
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Answer:
sorry sir/mam
Step-by-step explanation:
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Answer:
Step-by-step explanation:
x= -b±√b²-4ac/2a
D = b²-4ac = (-5)² - 4(4)(-1) = 25+16= 41
x = -(-5) ±√41/ 2(4)
x= 5+√41/8 , x= 5- √41/8
α=5+√41/8 , β= 5-√41/8
α²β + αβ² = αβ (α+β)
= (5+√41/8)(5-√41/8) [(5+√41/8)+(5-√41/8)]
= [(5)² - (√41)²]/8 [(5+5+√41-√41)/8]
= [25-41] [25] /8×8
= (-24)(25)/64
= -600/64 = -150/17
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