Math, asked by nagmahussaini, 2 months ago

if alpha and beta are the zeros of the quadratic polynomial p(x)=4x²-5x-1 find the value of alpha²beta+alphabeta²​

Answers

Answered by diwesh12
0

Answer:

sorry sir/mam

Step-by-step explanation:

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Answered by fayaaz1805
1

Answer:

Step-by-step explanation:

x= -b±√b²-4ac/2a

D = b²-4ac = (-5)² - 4(4)(-1) = 25+16= 41

x = -(-5) ±√41/ 2(4)

x= 5+√41/8 , x= 5- √41/8

α=5+√41/8 , β= 5-√41/8

α²β + αβ² = αβ (α+β)

                = (5+√41/8)(5-√41/8) [(5+√41/8)+(5-√41/8)]

                = [(5)² - (√41)²]/8 [(5+5+√41-√41)/8]

                = [25-41] [25] /8×8

                = (-24)(25)/64

                = -600/64 = -150/17

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