if alpha and beta are the zeros of the quadratic polynomial F(x)= x2 -px+q,then find the values of 1/alpha +1/beta?
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1/alfa + 1/ beta =alfa + beta /alfa * beta...
Now, Acc. to d given polynomial.....
alfa + beta =-b/a=p
alfa *beta =c/a=q
Therefore, req. answer =p/q
Now, Acc. to d given polynomial.....
alfa + beta =-b/a=p
alfa *beta =c/a=q
Therefore, req. answer =p/q
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★ Ello ★
here is your answer !!!
x² + bx+ c
are Quadratic. equation :-
x² - px + q
on comparing we get
a = 1
b = - p
c = q
now ,
zeroes are given :-
@ + ß = - p/ 1
=> - ( p / 1 )
= > p / 1
@ ß = q / 1
1 / @ + 1 ß.
=> ß + @ / @ß
=>p / q
=> p / q
hope it helps you dear !!
here is your answer !!!
x² + bx+ c
are Quadratic. equation :-
x² - px + q
on comparing we get
a = 1
b = - p
c = q
now ,
zeroes are given :-
@ + ß = - p/ 1
=> - ( p / 1 )
= > p / 1
@ ß = q / 1
1 / @ + 1 ß.
=> ß + @ / @ß
=>p / q
=> p / q
hope it helps you dear !!
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