if alpha and beta are the zeros of the quadratic polynomial f x is equal to x square- X + 4 find the value of alpha + beta minus alpha beta
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Answered by
5
Hey dear
we know that sum of zeroes = alpha + beta
=- coefficient of x/ coefficient of x²
=-(-1)/1
And product of zeroes=alpha/beta
= constant/coefficient of x²
=4/1
from this( alpha + beta)- alpha beta =
1/1-4/1
=1-4=-3
May this will help u
pls mark it as brainleist
we know that sum of zeroes = alpha + beta
=- coefficient of x/ coefficient of x²
=-(-1)/1
And product of zeroes=alpha/beta
= constant/coefficient of x²
=4/1
from this( alpha + beta)- alpha beta =
1/1-4/1
=1-4=-3
May this will help u
pls mark it as brainleist
Anonymous:
Yeah , Moderators
Answered by
7
Hey Mate !
Here is your solution :
Given,
f(x) = x² - x + 4.
α and β be its zeroes.
Here,
Coefficient of x² ( a ) = 1
Coefficient of x ( b ) = -1
Constant term ( c ) = 4
We know the relationship between zeroes and coefficients of x.
=> Sum of zeroes = -b/a
=> α + β = -( -1 ) / 1
=> α + β = 1 -------- ( 1 )
And,
=> Product of zeroes = c/a
=> αβ = 4/1
=> αβ = 4 -------- ( 2 ).
Now,
= ( α + β ) - α β
By substituting the value of ( 1 ) and ( 2 ),
= ( 1 ) - 4
= 1 - 4
= -3
The required answer is ( -3 ).
===================================
Hope it helps !!
Here is your solution :
Given,
f(x) = x² - x + 4.
α and β be its zeroes.
Here,
Coefficient of x² ( a ) = 1
Coefficient of x ( b ) = -1
Constant term ( c ) = 4
We know the relationship between zeroes and coefficients of x.
=> Sum of zeroes = -b/a
=> α + β = -( -1 ) / 1
=> α + β = 1 -------- ( 1 )
And,
=> Product of zeroes = c/a
=> αβ = 4/1
=> αβ = 4 -------- ( 2 ).
Now,
= ( α + β ) - α β
By substituting the value of ( 1 ) and ( 2 ),
= ( 1 ) - 4
= 1 - 4
= -3
The required answer is ( -3 ).
===================================
Hope it helps !!
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