if alpha and beta are the zeros of the quadratic polynomial x2-2+x then (1/alpha+1/beta)^2
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if alpha and beta are the zeros of the quadratic polynomial x2-2+x then (1/alpha+1/beta)^2
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1
Answer:
Solution
α+β=−1andαβ=−2.
(β+α)2−(β−α)2=4αβ
⇒(β−α)2=(α+β)2−4αβ=(−1)2−4×(−2)=9
⇒β−α=3.
∴ (1/α−1/β)
= (β−α)/αβ
= 3/−2
= −3/2.
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