Math, asked by Saba4826, 1 year ago

if alpha and beta are the zeros of the quadratic polynomial f(x)=ax2+bx+c then evaluate 1/alpha3+1/beta3

Answers

Answered by sprao534
59
Please see the attachment
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Answered by aquialaska
40

Answer:

we are given with Quadratic polynomial , f(x) = ax² + bx + c and α & β are zeroes.

We use the relation of coefficient and zeroes.i.e.,

\alpha+\beta=\frac{-b}{a}

\alpha\,\beta=\frac{c}{a}

Consider,

\frac{1}{\alpha^3}+\frac{1}{\beta^3}

\implies\frac{\alpha^3+\beta^3}{(\alpha\,\beta)^3}

\implies\frac{(\alpha+\beta)^3+3\apha\,\beta(\alpha+\beta)}{(\alpha\,\beta)^3}

\implies\frac{(\frac{-b}{a})^3+3\frac{c}{a}(\frac{-b}{a})}{(\frac{c}{a})^3}

\implies\frac{\frac{-b^3+3abc}{a^3}}{\frac{c^3}{a^3}}

\implies\frac{-b^3+3abc}{c^3}

\implies\frac{3abc-b^3}{c^3}

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