Math, asked by abhishek3322, 1 year ago

if alpha and beta are the zeros of the quadratic polynomial p of x
 = 4x {  }^{2}   -5x - 1
find the value of
 \alpha  {}^{2}  \beta  +  \alpha  \beta  {}^{2}

Answers

Answered by protestant
2
<h1>SOLUTIONS:</h1>

Given:p(x)=

4x ^{2} + - 5x - 1

To find the value of

 \alpha ^{2} \beta + \alpha \beta ^{2}

First find the sum of Zeroes and product.

Sum of Zeroes is =-(coefficient of x)/(coefficient of x^2)

 \alpha + \beta = - ( - 5) \div 4

 \alpha + \beta = 5 \div 4

Their products will be

=constant/coefficient of x^2

=

 \alpha \beta = - 1 \div 4

Now

 \alpha ^{2} \beta + \alpha \beta = \alpha \beta ( \alpha + \beta )

so, put the value of products and sum now.

Putting we got=-1/4(5/4)

=-5/16

So, the value is -5/16

Anonymous: Good Job Dude
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abhishek3322: Thanks for you valuable answer
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