If alpha and beta are the zeros of the quadratic polynomial fx = 2 x square - 4 x + 3 find the value of alpha 4 beta 2 + alpha square beta 4
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Answer:
Step-by-step explanation:
p(x)= (x)^2-4x +3
Using relation -
1) alpha + beta = -b/a
=> alpha + beta =-(-4)/1
=> alpha + beta = 4-----(1)
2) alpha * beta =c/a
=> alpha * beta = 3------(2)
Comparing equation (1) and(2) we get to know that one of the zeros is 1 and the other is 3.
So
A.T.Q.
We need to find the quadratic polynomial for the zeros 3*1=3 and 3*3 =9
Using relation -
1) alpha + beta =-b/a. 1) alpha* beta=c/a
=>3+9=-b/a. =>3*9=c/a
=>12=-b/a. =>27=c/a
So we can take a as 1
Hence , b=-12 and c =27
So the polynomial is(x)^-12x+27
For more clarification please see the attachment☺
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