if alpha and beta are the zeros of the quadratic polynomial f(x) =k Square +4x+4 such that alpha square +beta square =24 find the value of k
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chinnarakesh:
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According to the question,
α²+β² = 24
(α+β)² - 2(αβ)= 24
16/k² -8/k= 24
- = 24
= 24
16 - 8k = 24k²
24k² + 8k - 16 = 0
Dividing the eq. by 8
3k² + k - 4 = 0
3k² -3k + 4k - 4 = 0
3k ( k - 1) 4(k-1) = 0
Hence,
k = 1
Or
k =
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