if alpha and beta are the zeros of the x squared minus 4 x + 3 find the values of Alpha 4 beta Cube + aplha cube + beta 4
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x sq -4x +3=0
here a=1,b=-4 ,c=3
alpha + bita = -b/a
= 4
alpha.bits=c/a
= 3
Now alpha 4 beta cube + alpha cube beta 4
so alpha cube .beta cube(alpha + bita)[jus taking common]
Now (apha.beta)cube (alpha + bita)
(3)cube.(4)
27.4
= 108 Ans
here a=1,b=-4 ,c=3
alpha + bita = -b/a
= 4
alpha.bits=c/a
= 3
Now alpha 4 beta cube + alpha cube beta 4
so alpha cube .beta cube(alpha + bita)[jus taking common]
Now (apha.beta)cube (alpha + bita)
(3)cube.(4)
27.4
= 108 Ans
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