Question

if alpha and beta are the zeros of the zeros of the polynomial p(x)=9x²+ 9x +2 the find alpha² + beta ²​

Answer 1

Answer:

It's not English

Explanation:

It's mathematics

Answer 2

9x² + 9x + 2

Using determinant Formula,

D=b²-4ac

= (9)²-4(9)(2)

= 81-72

= 9

$\alpha = \frac{ - b + \sqrt{D} }{2(a)} \\ \: \: = \frac{ - 9 + \sqrt{9} }{2(9)} \\ \: = \frac{ - 9 + 3}{18} \\ \: = \frac{ - 6}{18} \\ \: = \frac{ - 1}{3}$

$\beta = \frac{ - b - \sqrt{D} }{2(a)} \\ \: = \frac{ - 9 - \sqrt{9} }{2(9)} \\ \: = \frac{ - 9 - 3}{18} \\ \: = \frac{ - 12}{18} \\ \: = \frac{ - 2}{3}$

${ \alpha }^{2} + { \beta }^{2}$

${( \frac{ - 1}{3} )}^{2} + {( \frac{ - 2}{3}) }^{2} \\ \frac{ 1}{9} + \frac{4}{9} \\ \frac{5}{9}$

keep smiling ❣️