If alpha and beta are the zeros of x^2+5x+5 find the value of alpha^-1 and beta^-1.
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Let given polynomial be
p(x)=x^2+5x+5
p(x)=0
x^2+5x+5=0
alpha and beta are the zeroes.
alpha=[-b+√(b^2-4ac)]/2a
=[-5+√(25-20)]/2
=[-5+√5]/2
Beta=[-b-√(b^2-4ac)]/2a
=[-5-√5]/2
alpha^-1=[(-5+√5)/2]^-1
=1/[-5+√5]/2
=2/(-5+√5)
beta^-1=[(-5-√5)/2]^-1
=2/(-5-√5)
p(x)=x^2+5x+5
p(x)=0
x^2+5x+5=0
alpha and beta are the zeroes.
alpha=[-b+√(b^2-4ac)]/2a
=[-5+√(25-20)]/2
=[-5+√5]/2
Beta=[-b-√(b^2-4ac)]/2a
=[-5-√5]/2
alpha^-1=[(-5+√5)/2]^-1
=1/[-5+√5]/2
=2/(-5+√5)
beta^-1=[(-5-√5)/2]^-1
=2/(-5-√5)
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