Question

if alpha and beta are the zeros of x square + 7x + 12 then find the value of one upon alpha + 1 upon beta minus 2 alpha beta

Answer 1

${x}^{2} + 7x + 12 = 0 \\ \alpha + \beta = - 7 \\ \alpha \beta = 12 \\ \frac{1}{ \alpha } + \frac{1}{ \beta } - 2 \alpha \beta \\ = \frac{ \alpha + \beta }{ \alpha \beta } - 2 \alpha \beta \\ = \frac{( - 7)}{12} - 2(12) \\ = \frac{ - 7}{12} - 24 \\ = \frac{ - 295}{12}$
hope it helps

Answer 2

Answer:

thanks for answering my question