if alpha and beta are two different values of theta lying between 0 and 2pi wch satisfy the equation 6 cos theta + 8 sin theta = 9 , find the value of sin ( alpha + beta )
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6 cos ∅ + 8 sin ∅ = 9
sin²∅ = 1 - cos²∅
6cos∅ + 8(1 - cos²∅) = 9
6cos∅ + 8 - 8cos²∅ - 9 = 0
8cos²∅ - 6cos∅ = 1 = 0
This is a quadratic equation
By letting cos∅ = y
We can re-write it as:
8y² - 6y + 1 = 0
The solution gives y = 0.5 or 0.25
∴ cos∅ = 0.5 or 0.25
and
∅ = 1.0472 rad or 1.3181 rad
The sum of the two angles = 1.0472 + 1.3181 = 2.3653 rad
Sin (∅ + β) = Sin 2.3653 = 0.7
sin²∅ = 1 - cos²∅
6cos∅ + 8(1 - cos²∅) = 9
6cos∅ + 8 - 8cos²∅ - 9 = 0
8cos²∅ - 6cos∅ = 1 = 0
This is a quadratic equation
By letting cos∅ = y
We can re-write it as:
8y² - 6y + 1 = 0
The solution gives y = 0.5 or 0.25
∴ cos∅ = 0.5 or 0.25
and
∅ = 1.0472 rad or 1.3181 rad
The sum of the two angles = 1.0472 + 1.3181 = 2.3653 rad
Sin (∅ + β) = Sin 2.3653 = 0.7
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Answer:
Step-by-step explanation:
6 cos ∅ + 8 sin ∅ = 9
sin²∅ = 1 - cos²∅
6cos∅ + 8(1 - cos²∅) = 9
6cos∅ + 8 - 8cos²∅ - 9 = 0
8cos²∅ - 6cos∅ = 1 = 0
This is a quadratic equation
By letting cos∅ = y
We can re-write it as:
8y² - 6y + 1 = 0
The solution gives y = 0.5 or 0.25
∴ cos∅ = 0.5 or 0.25
and
∅ = 1.0472 rad or 1.3181 rad
The sum of the two angles = 1.0472 + 1.3181 = 2.3653 rad
Sin (∅ + β) = Sin 2.3653 = 0.7
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