Question

If alpha and beta are two zeros of polynomial 3 x square-17 x +25 find alpha square +beta square and find alpha cube + beta cube

Answer 1

Step-by-step explanation:

3x²-17x+25

(3x²-17x+25)/3

x²-17/3+25/3

a=1x, b=17/3*1/2=17/6

x²-2(x)(-17/6)+(-17/6)²-(-17/6)²+25/3

ax²+bx+c=(a+b)²

[x-17/6]²=289/36-25/3=

[x-17/6]²=-11/36

There are no real roots

Answer 2

Answer:

answer attached in photo