if alpha and beta are two zeros of quadratic polynomial 2 x square - 3 x + 7 evaluate Alpha square + beta square
Answers
Answered by
11
Step-by-step explanation:
here is your answer
I hope this would help you
Attachments:
Answered by
5
Answer:
-19/4
Step-by-step explanation:
Given that ∝ and β are the zeroes of Quadratic Polynomial,
p(x) = 2x^2 - 3x + 7
We know, ∝ + β = -(Coefficient of x) / coefficient of x^2
∝β = Constant Term / coefficient of x^2
Hence, here ∝ + β = -(-3) / 2 = 3/2
∝β = 7/2
By Identity, (a+b)^2 = a^2 + b^2 + 2ab
(∝ + β)^2 = ∝^2 + β^2 + 2∝β
( 3/2)^2 = ∝^2 + β^2 + 2 (7/2)
∝^2 + β^2 = 9/4 - 7
∝^2 + β^2 = 9- 28 / 4
∴ ∝^2 + β^2 = -19/4
Hope this helps you..!!
Similar questions