if alpha and beta are zeroes of 2x^2-3x+1 find alpha^2 and beta^2
Answers
Answer:
α² = 1 and β² = 1/4
Step-by-step explanation:
Given :
α and β are the zeroes of the polynomial 2x² - 3x + 1
To find :
the value of α² and β²
Solution :
Let's find the zeroes of the polynomial first and then get the value of α² and β² by substituting.
Finding the zeroes by splitting middle term, [ sum-product pattern ]
2x² - 3x + 1 = 0
2x² - 2x - x + 1 = 0
2x(x - 1) - 1(x - 1) = 0
(x - 1) (2x - 1) = 0
- x - 1 = 0 ; x = +1
- 2x - 1 = 0 ; x = 1/2
The zeroes of the given polynomial are 1 and 1/2.
Let
- α = 1
- β = 1/2
So,
α² = 1² = 1
β² = (1/2)² = 1/4
______________________________
Know about Quadratic Polynomial :
✯ It is a polynomial of degree 2
✯ General form :
ax² + bx + c = 0
✯ Determinant, D = b² - 4ac
✯ Based on the value of Determinant, we can define the nature of roots.
D > 0 ; real and unequal roots
D = 0 ; real and equal roots
D < 0 ; no real roots i.e., imaginary
✯ Relationship between zeroes and coefficients :
✩ Sum of zeroes = -b/a
✩ Product of zeroes = c/a