Question

if alpha and beta are zeroes of 2x^2-3x then calculate alpha +beta + alpha beta?​

Answer 1

Step by Step solution:

${2x}^{2} - 3x$

Sum of zeros

$\alpha + \beta = - ( - \frac{3}{2} ) \\ = \frac{3}{2}$

Product of zeros

$\alpha \beta = \frac{0}{2} \\ = 0$

$\alpha + \beta + \alpha \beta \\ \\ ( \alpha + \beta ) + \alpha \beta \\ \\ \frac{3}{2} + 0 \\ \\ = \frac{3}{2}$

Answer:

3/2