Question

If alpha and beta are zeroes of 3x2_17x+24 find 1/a+1/beta

Answer 1

Answer:

Step-by-step explanation:

$3x^{2} - 17x + 24 = 0$

Solving by splitting the terms

$3x^{2} - 17x + 24 = 0\\3x^{2} - (9+8)x + 24 = 0$

$3x^{2} -9x-8x + 24 = 0$

3x(x-3) - 8(x-3) = 0

(3x-8)(x-3) = 0

3x-8=0 ;; x-3=0

x = 8/3 ;; x =3

$\frac{1}{\alpha } = 1/\frac{8}{3} \\\frac{1}{\alpha } = \frac{3}{8}$

$\frac{1}{\beta } = \frac{1}{3}$

So, add

$\frac{3}{8} +\frac{1}{3} \\\\\frac{9+8}{24}\\\\\frac{17}{24}$

Hope you understand well