Question

If alpha and beta are zeroes of 3x2-4x-7 then form a quadratic equation whose zeroes are 1/alpha and1/beta

Answer 1

Im not sure if its correct

Answer 2

Answer:

7x^2+4x-3

Step-by-step explanation:

given,

polynomial = 3x^2-4x-7

we know,

ax^2-bx-c

•°•a=3 , b=-4, c=-7

sum of zeroes= -b/a

ie. alpha+beta = -(-4)/3

alpha+beta = 4/3

product of zeroes= c/a

ie. alpha×beta= -7/3

we know,

x^2-(sum of roots)x+(product of roots)

•°•given,

zeroes = 1/alpha &1/beta

•°• sum of Roots= 1/alpha+1/beta

= Bata+alpha/alpha× beta

=(4/3)/(-7×3)

= 4/3×3/-7

= -4/7

again

product of roots= 1/alpha×1/beta

= 1/alpha×beta

=1/(-7/3)

=-3/7

•°• required polynomial is x^2-(-4/7)x+(-3/7)

=x^2+4/7x-3/7

=7^2x+4x-3/7=0

7x^2+4x-2. (and)

hope it will you