Question

If alpha and beta are zeroes of a quadratic polynomial x2-5 then form a quadratic polynomial whose zeroes are 1+alpha and 1+beta

Answer 1

Step-by-step explanation:

alpha + beta = -b/a

alpha × beta =c/a

2x - 5 + 0 = 0

alpha +beta = -(-5)/2 =5/2

alpha × beta = 0 /2 = 0

(1+alpha) (1 + beta )

${1}^{2} + (5 \div 2)1 + 0$

$1 + (5 \div 2)$

$(2 + 5) \div 2$

7÷2