if alpha and beta are zeroes of equations p(x) = 3x^2+ 11x + a form a quadratic equations whose zeroes are 3a and 3b
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Eq. = 3x² + 11x + a
Sum of zeroes = - (coefficient of x) / (coefficient of x²)
==> α + β = - 11/3
Multiply both sides by 3
==> 3α + 3β = -11 ...(1)
Also,
Product of zeroes = ( constant term ) / ( coefficient of x² )
==> αβ = a / 3
Multiply each equation by 9
==> 3α × 3β = 3a ...(1)
We know,
Quad. Equation = x² - ( sum of zeroes )x + ( product of zeroes )
==> x² - ( - 11)x + 3a
==> x² + 11x + 3a
Hence, the required quadratic equation is
☛ x² + 11x + 3a
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