if alpha and beta are zeroes of p(x)=x^2-x-1. find the value of alpha cube +beta cube.
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Alpha = a & beta = b
Answer:
4
Step-by-step explanation:
Polynomials written in form of x^2 - Sx + P, represent S as sum of roots anf P as product of roots.
So, here,
Sum = a + b = 1
Product = ab = - 1
= > a + b = 1
Cube on both sides -
= > ( a + b )³ = 1³
= > a³ + b³ + 3ab( a + b ) = 1
= > a³ + b³ + 3(product)(sum) = 1
= > a³ + b³ + 3(-1)(1) = 1
= > a³ + b³ - 3 = 1
= > a³ + b³ = 1+ 3
= > a³ + b³ = 4
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