Question

if alpha and beta are zeroes of P(x)=x square-34+x then find a+p+aẞ​

Answer 1

$\huge{\underline{\underline{\mathfrak{\green{\bf{Questions:-}}}}}}$.

• If $\alpha\:and\:\:\beta$ are Zeros of P(x) = x² - 34 +x , then find $\:(\alpha+\beta+\alpha\beta)$.

$\huge{\underline{\underline{\mathfrak{\bf{Solution:-}}}}}$.

Given Equation

• $\large\boxed{\:p(x)\:=\:(x^2+x-34)}$

• $\alpha\:and\beta\:are\:Zeros$

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We Know ,

$\boxed{\:Sum\:of\:Zeros\:=\frac{-(cofficiant\:of\:x)}{(Cofficient\:of\:x^2)}}$

$\implies\:(\alpha+\beta)\:=\frac{-(1)}{1}$

$\implies\:(\alpha+\beta)\:=\:(-1)$........(1)

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Again,

$\large\boxed{\:Product\:of\:Zeros\:=\frac{Constant\:part}{Coefficient\:of\:x^2}}$

$\implies\:(\alpha\beta)\:=\frac{-34}{1}$

$\implies\:(\alpha\beta)\:=\:-34$..........(2)

$\large{\underline{\underline{\mathfrak{\bf{Calculate\:here:-}}}}}$.

$\implies\:(\alpha+\beta+\alpha\beta)$

$\implies\:(\:-1\:+\:(-34)$

$\implies\:(\:-35)$

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$\huge{\underline{\underline{\mathfrak{\green{\bf{Answer:-}}}}}}$.

$\red{\bold{\:-35}}$