Question

if alpha and beta are zeroes of p(x)= x2- 5x +6, then find the value of alpha +beta - 3 alpha.beta

Answer 1

Alpha +beta=5/1
Alpha beta=6/1
Your answer =5-3(6)=-13

Answer 2

Answer:

-13

Step-by-step explanation:

Concept

The polynomial equation whose highest degree is two is called a quadratic equation. The equation is given by ax² + bx + c = 0, where a ≠ 0.

Given

$\alpha$ and $\beta$ are zero of p(x)=$x^{2} -5x+6$

Find

$\alpha +\beta -3\alpha \beta$ value

Solution

$x^{2}-5 x+6$

$a=1, b=-5, c=6$

$\alpha+\beta=\frac{-b}{a}=\frac{-(-5)}{1}=5$

$\alpha \beta=\frac{c}{a}=\frac{6}{1}=6$

$\alpha+\beta-3 \alpha \beta$

$=5-3(6)$

$=5-18=-13$

$\alpha+\beta-3 \alpha \beta=-13$

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