if alpha and beta are zeroes of polynomial 6x²-7x-3 , then form a quadratic polynomial where zeroes are 2alpha and 2beta.
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6xsquare-9x+2x-3
3x(2x-3)+1(2x-3)
(2x-3) (3x+1)
2x-3=0
2x=3
x=3/2
3x+1=0
3x=-1
x=-1/3
so the Zeroes are 3/2 &-1/3
3/2×2=6/2=3
-1/3×2=-2/3
so zeroes are 3 and -2/3
3x(2x-3)+1(2x-3)
(2x-3) (3x+1)
2x-3=0
2x=3
x=3/2
3x+1=0
3x=-1
x=-1/3
so the Zeroes are 3/2 &-1/3
3/2×2=6/2=3
-1/3×2=-2/3
so zeroes are 3 and -2/3
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