if alpha and beta are zeroes of polynomial p(x)=x^-(k+6)x+2(2k-1)then find the value of k if aipha +beta=alpha×beta/2
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hey
let alpha be a and beta be b (for my convenience)
2(a+b) = ab
2(k-6) = 4k - 2
2k - 6 = 4k - 2
4k - 2k = -6 + 2
2k = -4
k = -4/2
k = -2
let alpha be a and beta be b (for my convenience)
2(a+b) = ab
2(k-6) = 4k - 2
2k - 6 = 4k - 2
4k - 2k = -6 + 2
2k = -4
k = -4/2
k = -2
Answered by
1
Answer:
k=7
Step-by-step explanation:
α+β=1/2×α×β
α+β= -b/a = -[ - (k+6)]
α×β= c/a = 2(2k-1) = 4k-2
Therefore,
k+6 = 1/2 ×( 4k-2)
2(k+6) = 4k-2
2k+12 = 4k-2
-4k+2k = -2-12
k = -14/-2
k=7
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