if alpha and beta are zeroes of polynomial x²- 5x+k such that alpha - beta =1. Find the value of k.
plz answer fast.. it's urgent..
Answers
Answered by
5
Hola Estimado !
______________________________________________________________
let α and β are two zeros of given polynomial
Polynomial = x²-5x+k
also α-β = 1
α = 1+β
we know c/a = product of zeros
k = αβ
k = (1+β )(β) ∵[α=1+β]
k = β+β²______________(1)
also, -b/a = sum of zeros
5 = α+β
5 = β+1+β
5 = 2β+1
4 = 2β
β = 2
put value of β in equation 1
we get ,
k= β+β²
k= 2+2²
k= 2+ 4
k= 6
____________________________________________________________
______________________________________________________________
let α and β are two zeros of given polynomial
Polynomial = x²-5x+k
also α-β = 1
α = 1+β
we know c/a = product of zeros
k = αβ
k = (1+β )(β) ∵[α=1+β]
k = β+β²______________(1)
also, -b/a = sum of zeros
5 = α+β
5 = β+1+β
5 = 2β+1
4 = 2β
β = 2
put value of β in equation 1
we get ,
k= β+β²
k= 2+2²
k= 2+ 4
k= 6
____________________________________________________________
Anonymous:
Well explained answer ^_^
Answered by
0
Given that ;
- p(x) = x² - 5x + k
- from p(x) , a = 1 , b = -5 , c = k
- α - β = 1
- so , α = 1 + β
To find :
- value of k ?
Solution ;-
we know that
α+β = -b/a
so ,
1 + β + β = -(-5)/1 = 5
2β = 5-1 = 4
so , β = 2
so , α = 1 + β = 1+2 = 3 , α = 3
then ,
we know that , αβ = c/a
then , (2)(3) = k/1 = k
k = 6
- value of k = 6
Similar questions