if alpha and beta are zeroes of quadratic polynomial 2x^2+5x+k,find the value such that (alpha+beta)^2-alpha and beta=24
Answers
Answered by
146
2x² + 5x + k = 0 is the given quadratic equation and it is given that
(α+β)² - α.β = 24 ....(i)
As we know that,
α+β = -b/a = -5/2 ....(ii)
and α.β = c/a = k/2 ....(iii)
Putting values of (ii) & (iii) in (i) , we get
(-5/2)² - (k/2) = 24
=> 25/4 - k/2 = 24
=> (25-2k)/4 = 24
=> 25 - 2k = 96
=> 2k = 25 - 96
=> 2k = -71
=> k = -71/2
hope it helps (￢‿￢ )
happy to help :)
#IAMALPHA
(α+β)² - α.β = 24 ....(i)
As we know that,
α+β = -b/a = -5/2 ....(ii)
and α.β = c/a = k/2 ....(iii)
Putting values of (ii) & (iii) in (i) , we get
(-5/2)² - (k/2) = 24
=> 25/4 - k/2 = 24
=> (25-2k)/4 = 24
=> 25 - 2k = 96
=> 2k = 25 - 96
=> 2k = -71
=> k = -71/2
hope it helps (￢‿￢ )
happy to help :)
#IAMALPHA
Answered by
19
Answer:
Step-by-step explanation: pls go through the attachment for the answer
Attachments:
Similar questions