if alpha and beta are zeroes of quadratic polynomial ax²+bx+c, evaluate α²+β²
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Answer:
α² + ß² = b²/a² - 2c/a
Note:
★ The possible values of variable for which the polynomial becomes zero are called its zeros.
★ A quadratic polynomial can have atmost two zeros.
★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;
Sum of zeros , (α + ß) = -b/a
Product of zeros , αß = c/a
Solution:
Here,
The given quadratic polynomial is :
ax² + bx + c .
Also,
α and ß are the zeros of the given quadratic polynomial , thus ;
α + ß = -b/a
αß = c/a
Now,
=> (α + ß)² = α² + ß² + 2αß
=> α² + ß² = (α + ß)² - 2αß
= (-b/a)² - 2(c/a)
= b²/a² - 2c/a
Hence,
α² + ß² = b²/a² - 2c/a
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