Question

If alpha and beta are zeroes of quadratic polynomial f(x)=ax^2+ bx+c, then evaluate alpha - beta

Answer 1

Hello friend your answer is
α and β are the zeros then Ax²+Bx+C
α-β find..
Sum of zeroes = α+β
-b/a=
-B/A
Product of zeroes =c/a
C/A
now α-β=(α-β)²=(α+β)²-4αβ
use this identity
=-B/A-4C/A
-B/A-4C/A
-B-4C/A


α-β=√-B-4C/A
I hope it helps your

Answer 2

Answer:

α-β=√-B-4C/A

Step-by-step explanation:

α and β are the zeros then Ax²+Bx+C

α-β find..

Sum of zeroes = α+β

-b/a=

-B/A

Product of zeroes =c/a

C/A

now α-β=(α-β)²=(α+β)²-4αβ

use this identity

=-B/A-4C/A

-B/A-4C/A

-B-4C/A

α-β=√-B-4C/A