if alpha and beta are zeroes of quadratic polynomial f(x)= ax²+bx+c, evaluate alpha²+beta³
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Answer:
(b²-2ac)/a²
Step-by-step explanation:
f(x)= ax²+bx+c
alpha+beta = -b/a
alpha×beta = c/a
alpha²+beta²= (alpha+beta)²-2alpha×beta
= (-b/a)²-2c/a
= b²/a²-2c/a
= (b²-2ac)/a²
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