If alpha and beta are zeroes of the polynomial 2x^2-3x+8 then find {[(alpha)^-2]+[(beta)^-2]}
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★Heya★
GIVEN QUESTION IS :-
2x² - 3x + 8
Find ( Alfa )-² + ( Beta )-²
EXP:-
(Alfa + Beta) = 3/2
And
( Alfa × Beta ) = 8/2 = 4
Alfa² + Beta² = ( Alfa + Beta )² -2 Alfa × Beta
=>
(Alfa)-² + (Beta)-² =
{(Alfa)² + (Beta)²}/ {(Alfa)² + (Beta)² }
=>
{ (Alfa)-² + (Beta)-² } =
(3/2)² - 2 × ( 4 )
___________
16
=>
{(Alfa)-² + (Beta)-²} = -92
GIVEN QUESTION IS :-
2x² - 3x + 8
Find ( Alfa )-² + ( Beta )-²
EXP:-
(Alfa + Beta) = 3/2
And
( Alfa × Beta ) = 8/2 = 4
Alfa² + Beta² = ( Alfa + Beta )² -2 Alfa × Beta
=>
(Alfa)-² + (Beta)-² =
{(Alfa)² + (Beta)²}/ {(Alfa)² + (Beta)² }
=>
{ (Alfa)-² + (Beta)-² } =
(3/2)² - 2 × ( 4 )
___________
16
=>
{(Alfa)-² + (Beta)-²} = -92
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