If alpha and beta are zeroes of the polynomial {2x}2-5x+7 then find the quadratic Polynomial where zeroes are { 3 alpha + 4 beta } and {4 alpha + 3 beta }
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let sum of roots -b/a= -7( alpha+beta)
product of roots c/a=12alpha*2+9alpha;beta+16alpha;beta+12beta*2
=12alpha*2+25alpha;beta+12beta*2
X*2-7(alpha+beta)+12(alpha*2+beta*2+24beta;alpha)+alpha;beta
let alpha be. =@
let beta be=$
for convince
given from above
(@+$)=5/2
-7(@+$)=-7(5/2)
@$=7/2
12(@+$)*2=12(25/4)
so the equation is
x*2-(-7(5/2))x+12(25/4)+7/2
x*2+19/2x+150/2+7/2
x*2+19/2x+157/2=0
2x*2+19x+157
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