If alpha and beta are zeroes of the polynomial 2x²-3x+k such that alpha-beta =1, find the value of k.
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Answer:
k = 5/8
Step-by-step explanation:
α and β are zeroes of the polynomial 2x²-3x+k
a= coefficient of x² = 2
b = coefficient of x = -3
c = constant term = k
Sum of zeros = α+β = -b/a = - (-3/2) = 3/2
Product of zeros = αβ = c/a = k/2
(α-β)² = (α+β)²-4αβ
putting the values of (α-β) = 1, (α+β) = 3/2 and αβ = k/2
1² = (3/2)² - 4 × (k/2)
1 = (9/4) -(4k/2)
1 = (9/4) - 2k
1-(9/4) = -2k
(4-9)/4 = -2k
-5/4 = -2k
2k = 5/4
k = (5/4) × (1/2)
k = 5/8
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