If alpha and beta are zeroes of the polynomial 3s^2-6s^2+4 find alpha/beta+beta/alpha+2(1/alpha+1/beta)+3alphabeta
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We have α+β=2 and αβ=43.
The first two terms add up to α2+β2αβ, which is (α+β)2−2αβαβ. This is 1.
The term 2(1α+1β), that is, 2(α+βαβ), is equal to 3, and the term 3αβ is equal to 4.
The sum of all the terms is 8.
The first two terms add up to α2+β2αβ, which is (α+β)2−2αβαβ. This is 1.
The term 2(1α+1β), that is, 2(α+βαβ), is equal to 3, and the term 3αβ is equal to 4.
The sum of all the terms is 8.
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