If alpha and beta are zeroes of the polynomial p(x) =x²+3x+2, find (1/alpha²)+(1/beta²)
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.sum of roots, a=-3
product of roots=2
1/a²+1/b²= a²+b²/(ab)²={ (a+b)²-2ab}/(ab)²
=(-3² - 2*2)/2²
=5/4
product of roots=2
1/a²+1/b²= a²+b²/(ab)²={ (a+b)²-2ab}/(ab)²
=(-3² - 2*2)/2²
=5/4
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