Question

if alpha and beta are zeroes of the polynomial x^2-2x-8, then form a quadratic polynomial whose zeroes are 2alpha and 2beta

Answer 1

Hi now we are going to use transformation method we use this only when the roots are symmetry -
2alpha be x so alpha = x/2 alpha is the root of the given equation so it will satisfy it so we have (alpha) ² - 2(ALPHA) - 8=0 SO Putting values of alpha we get x²-4x-32=0 is the required equation