if alpha and beta are zeroes of the polynomial x^2-4x+8, find the quadratic polynomial whose zeroes are 1 by alpha and 1 by beta
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a = 1 , b = -4, c = 8
sum of zero= -b/a
alpha+bita = -(-4)/1
alpha+bita =4
product of zero=c/a
alpha×bita = 8/1=8
1/alpha+1/bita
1/alpha+1/bita
bita+alpha / bita alpha
4/8=1/2
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