If alpha and beta are zeroes of the polynomial x2 - 6x + a.Find the value of a if 3alpha + 2beta = 0
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Given : alpha and beta are zeroes of the polynomial x2 - 6x + a , 3alpha + 2beta = 0
To find : Value of a
Solution:
x² - 6x + a = 0
α & β are zeroes
α + β = 6
αβ = a
α + β = 6 Eq1
3α + 2β = 0 Eq2
Eq2 - 2 * Eq1
=> α = -12
-12 + β = 6
=> β = 18
αβ = a
=> (-12)(18) = a
=> a = -216
Value of a = - 216
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