Question

If alpha and beta are zeroes of the polynomial x2-8x+k such that alpha-beta=2 , then find k

Answer 1

Answer:

15

Step-by-step explanation:

according to the quadratic equation

the sum of the roots = alpha + beta= - b/a and

product of roots = aplha x beta=c/a

But given quadratic the values of a= 1, b=-8 c= k

Alpha +beta =8

Alpha-beta=2

------—------------------

2alpha = 10

Alpha= 5

Beta =3

So alpha*beta=k

5*3=k

15=k

Answer 2

Answer:

Here is Your answer

Step-by-step explanation:

x2-8x+k , alpha-beta=2

a= 1

b= -8

c= k

alpha-beta=2

alpha=2+beta

sum of zeroes= -b/a

alpha+beta= -b/a

(2+beta)+beta= 8/1

2+2beta=8

2(1+beta)= 8

1+beta= 4

beta= 4-1

beta= 3

alpha= 2+beta

=2+3= 5

product of zeroes= c/a

alpha*beta=c/a

5*3= k/1

15=k