Question

If alpha and beta are zeroes of the quadratic polynomial x^2-6x+8 then find the value of A/B+B/A

Answer 1

Answer:

5/2

Step-by-step explanation:

A + B = -(-6)/1 = 6

AB = 8

A/B+ B/A = A^2 + B^2 / AB

Now, (A + B)^2 = A^2 + B^2 + 2AB

So, A^2 + B^2 = (A + B)^2 - 2AB

Therefore,

A/B + B/A = (A + B)^2 - 2AB/AB

=> (6)^2 -2.8/8

=> 36 - 16/8

=> 20/8

or, 5/2 (Answer)

Thank You!!

Answer 2

Answer:

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