If alpha and beta are zeroes of the quadratic polynomial x^-6x+a,find the value of 'a'.If 3alpha +2beta =20
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AS alpha and beta are zeroes
So alpha + beta = 6 ( - coeff. of x/ coefficient of x^2)......(1)
Also as given 3 alpha + 2 beta = 20
Multiply (1) by 3
3 alpha + 3 beta = 18
3 alpha + 2 beta = 20( given)
subtract
beta = -2
Put in given
3 alpha + 2(-2) = 20
3 alpha = 24
alpha = 8
As product of roots = alpha × beta = a
So 8× -2 = a
-16 = a
So alpha + beta = 6 ( - coeff. of x/ coefficient of x^2)......(1)
Also as given 3 alpha + 2 beta = 20
Multiply (1) by 3
3 alpha + 3 beta = 18
3 alpha + 2 beta = 20( given)
subtract
beta = -2
Put in given
3 alpha + 2(-2) = 20
3 alpha = 24
alpha = 8
As product of roots = alpha × beta = a
So 8× -2 = a
-16 = a
Answered by
3
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