Question

If alpha and beta are zeroes of x^2-6x+a ,find a if
$3 \alpha + 2 \beta = 20$
Kindly help
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Answer 1

Answer:

a = -16

Step-by-step explanation:

3 alpha + 2 beta = 20

alpha + beta = 6 (as alpha = beta = -b/a)

3 alpha + 2 beta = 20 --(i)

2 alpha + 2 beta = 12 --(ii)

eq (i) and (ii)

alpha = 8

3(8) + 2 beta = 20

beta = -2

alpha x beta = c/a

8 x -2 = a

a = -16